Tripod5G > he context in which that variable is used

3pod PHP Learning

"color" => "yellow",
"taste" => "paste-y",
"shape" => "banana-shaped"
)
);
echo $a["apple"]["taste"]; # will output "sweet"
?>
Objects
Object Initialization
To initialize an object, you use the new statement to instantiate the object to a variable.
class foo {
function do_foo () {
echo "Doing foo.";
}
}
$bar = new foo;
$bar -> do_foo ();
Type juggling
PHP does not require (or support) explicit type definition in variable declaration; a variable’s type is
determined by the context in which that variable is used. That is to say, if you assign a string value to
variable var, varbecomes a string. If you then assign an integer value to var, it becomes an integer.
An example of PHP’s automatic type conversion is the addition operator ’+’. If any of the operands is a
double, then all operands are evaluated as doubles, and the result will be a double. Otherwise, the
operands will be interpreted as integers, and the result will also be an integer. Note that this does NOT
change the types of the operands themselves; the only change is in how the operands are evaluated.
$foo = "0"; // $foo is string (ASCII 48)
$foo++; // $foo is the string "1" (ASCII 49)
$foo += 1; // $foo is now an integer (2)
84

Next >>

Tripod >> 3pod Tips & Learning and manuals for educations